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April 18, 2014

April 18, 2014

Posted by **Fai** on Saturday, December 28, 2013 at 11:48am.

- no, math -
**Damon**, Saturday, December 28, 2013 at 12:34pmtry 400 ml of 5% and 200 ml of 20% for example then you need NONE of the 50%.

Unless you have another criterion, the problem has many solutions.

- steve for your solution -
**Steve**, Sunday, December 29, 2013 at 6:23pmIf the amounts of the three solutions are x,y,z, respectively, then all you have given is

x+y+z = 600

.50x + .20y + .05z = .10*600

There are many solutions (as it were), such as

5% 20% 50%

400 200 0

440 140 60

500 50 50

520 20 60

533 0 67

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