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July 24, 2014

July 24, 2014

Posted by **Miley** on Friday, December 27, 2013 at 9:29am.

Also how do you solve this kind of question

- Math -
**Reiny**, Friday, December 27, 2013 at 10:24amnotice that in the place of x in f(x) you now find a -6

so in the expression , replace x with -6 as well

f(x) = 7x^3+13x^3-3x^2

f(-6) = 7(-6)^3 + 13(-6)^3 - 3(-6)^2

= ...

I suspect a typo, why would you have two different cubic terms ?

- Math -
**Miley**, Friday, December 27, 2013 at 4:00pmSo for this kind of question. You just replace the variables right?

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