suppose that a population of skunks lives on an isolated island is 500 skunks are present today and the birth rate is 65 per week and the death is 47 per week how many skunks to you predict will be on the island 105 days from now and what would a graph population versus time look for this population?
I just did the Unit 3 Lesson 1 Populations Quick Check for science 8B in Texas Connections Academy Houston. I got a 100% using these answers:
1. C.
2. B.
3. D.
4. A.
For anyone who wants an explanation for question one (the skunk question), here it is:
105 days is 15 weeks.
65 births - 47 deaths = 18 skunks added to the population every week
In 15 weeks, the population will have grown by 270 skunks
In 15 weeks, the total skunk population will be 770.
As you can see, the skunk population has grown drastically.
Hope this helps! 👍✌
Connexus Helper
100
Thx connexus helper pog
SOMEBODY JUST TELL ME THE ANSWER!!!!!! (this is urgent)
answers for connexus are
1. c
2. b
3. d
4. a
By the way, that is not a very likely population model. In general the more skunks you have, the more babies you get which results in an exponential curve up and not a straight line. The only way to stop the skunks from over running the place is to have a predator that also has a lot of babies and slows the growth rate down.
1. B
3 d
idek is right 100
105 days is 15 weeks
w is dependent variable meaning weeks
p = 500 + 65 * w - 47 * w
or
p = 500 + 18 w
if w = 15 then
p = 500 + 18 * 15
which is 770
That is a linear equation, straight line crossing the y axis at 500 and rising with slope 18 if the abscissa is weeks.