A floor mat weighing 220 N is 4 m long, 3 m wide, and 0.04 m thick. How much pressure is exerted by the mat against the floor, in Pascals to two decimal places?

Recall that Pressure is just Force over a unit Area, or

P = F/A
We are given the force (which is 220 N), therefore, we only need to find area.
A = L*W
A = 4*3 = 12 m
Therefore,
P = 220 / 12
P = 18.33 N/m^2
P = 18.33 Pa

Hope this helps :3

thanks Jai

To calculate the pressure exerted by the mat against the floor, we can use the formula:

Pressure = Force/Area

First, let's calculate the area of the mat:

Area = length x width
Area = 4 m x 3 m
Area = 12 m^2

Now, let's plug in the values into the formula:

Pressure = 220 N / 12 m^2
Pressure ≈ 18.33 Pascals

Therefore, the pressure exerted by the mat against the floor is approximately 18.33 Pascals.

To calculate the pressure exerted by the mat against the floor, we will use the formula:

Pressure = Force / Area

First, we need to find the area of the mat. The area of a rectangle is given by:

Area = Length × Width

In this case, the length of the mat is 4 m and the width is 3 m, so:

Area = 4 m × 3 m = 12 m²

Next, we need to convert the weight of the mat from Newtons to force. Weight is the force exerted by an object due to gravity, and it is calculated using the equation:

Force = Mass × Gravity

However, in this case, we are given the weight (220 N), not the mass. The weight is equal to the mass multiplied by the acceleration due to gravity (approximately 9.8 m/s²). Therefore, we can rearrange the equation to calculate the mass:

Mass = Force / Gravity

Mass = 220 N / 9.8 m/s² ≈ 22.45 kg

Now, we can substitute the values into the pressure formula:

Pressure = 220 N / 12 m²

Pressure ≈ 18.33 N/m² or 18.33 Pa (to two decimal places)

Therefore, the pressure exerted by the mat against the floor is approximately 18.33 Pascals.