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August 1, 2014

August 1, 2014

Posted by **Bryan** on Thursday, December 19, 2013 at 7:26pm.

(b) What percentage of the initial kinetic energy will be lost in the collision?

- Physics- hard problem -
**Damon**, Thursday, December 19, 2013 at 8:02pmNo, not hard, conservation of momentum

Initial north momentum =

(14000 N/9.81 m/s^2) (40000m/3600 s)

Initial east momentum =

(7000/9.81)(62000/3600)

Final north and east momentums are the same

total mass = m = 21000/9.81

m v cos T = initial east momentum

m v sin T = initial north momentum

solve for T, the angle up from east axis

then get v, the speed

Vnorth = v sin T

Veast = v cos T

Final ke = (1/2) m v^2

initial ke = (1/2)m1 initial speed1 ^2 + (1/2) m2 initial speed2^2

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