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Physics- hard problem

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A 14000 N automobile travels at a speed of 40 km/h northward along a street, and a 7000 N sports car travels at a speed of 62 km/h eastward along an intersecting street.(a) If neither driver brakes and the cars collide at the intersection and lock bumpers, what will the velocity of the cars be immediately after the collision?
(b) What percentage of the initial kinetic energy will be lost in the collision?

  • Physics- hard problem - ,

    No, not hard, conservation of momentum

    Initial north momentum =
    (14000 N/9.81 m/s^2) (40000m/3600 s)

    Initial east momentum =
    (7000/9.81)(62000/3600)

    Final north and east momentums are the same
    total mass = m = 21000/9.81
    m v cos T = initial east momentum
    m v sin T = initial north momentum
    solve for T, the angle up from east axis
    then get v, the speed
    Vnorth = v sin T
    Veast = v cos T

    Final ke = (1/2) m v^2
    initial ke = (1/2)m1 initial speed1 ^2 + (1/2) m2 initial speed2^2

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