Posted by **Bryan** on Thursday, December 19, 2013 at 7:26pm.

A 14000 N automobile travels at a speed of 40 km/h northward along a street, and a 7000 N sports car travels at a speed of 62 km/h eastward along an intersecting street.(a) If neither driver brakes and the cars collide at the intersection and lock bumpers, what will the velocity of the cars be immediately after the collision?

(b) What percentage of the initial kinetic energy will be lost in the collision?

- Physics- hard problem -
**Damon**, Thursday, December 19, 2013 at 8:02pm
No, not hard, conservation of momentum

Initial north momentum =

(14000 N/9.81 m/s^2) (40000m/3600 s)

Initial east momentum =

(7000/9.81)(62000/3600)

Final north and east momentums are the same

total mass = m = 21000/9.81

m v cos T = initial east momentum

m v sin T = initial north momentum

solve for T, the angle up from east axis

then get v, the speed

Vnorth = v sin T

Veast = v cos T

Final ke = (1/2) m v^2

initial ke = (1/2)m1 initial speed1 ^2 + (1/2) m2 initial speed2^2

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