Posted by **peter** on Thursday, December 19, 2013 at 12:39pm.

If # (a,b,c,d)means you raise b,c and d to the power of a and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?

2^a + 3^a + 4^a = 89

1^a + 1^a + 1^a = 89

3^a = 89

a = 86

an I do it right

- math (Reiny) -
**peter**, Thursday, December 19, 2013 at 12:42pm
If # (a,b,c,d)means you raise b,c and d to the power of d and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?

2^d + 3^d + 4^d = 89

1^d + 1^d + 1^d = 89

3^d = 89

d = 86

- math (Reiny) -
**peter**, Thursday, December 19, 2013 at 12:47pm
If # (a,b,c,d)means you raise b,c and d to the power of a and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?

a. 8

b. 9

c. 64

d. 81

e. 90

please answer and explain

- math (Reiny) -
**peter**, Thursday, December 19, 2013 at 1:07pm
2 + 3^a + 4^a + d^a = 89

2 + 1^a + 1^a + d^a = 89

2^a + d^a = 87

- math (Reiny) -
**peter**, Thursday, December 19, 2013 at 1:10pm
I don't know how to do

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