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math (Reiny)

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If # (a,b,c,d)means you raise b,c and d to the power of a and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?

2^a + 3^a + 4^a = 89
1^a + 1^a + 1^a = 89
3^a = 89
a = 86

an I do it right

  • math (Reiny) -

    If # (a,b,c,d)means you raise b,c and d to the power of d and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?

    2^d + 3^d + 4^d = 89
    1^d + 1^d + 1^d = 89
    3^d = 89
    d = 86

  • math (Reiny) -

    If # (a,b,c,d)means you raise b,c and d to the power of a and then take the sum of the resulting values, and # (2,3,4,d)=89,then d=?

    a. 8
    b. 9
    c. 64
    d. 81
    e. 90

    please answer and explain

  • math (Reiny) -

    2 + 3^a + 4^a + d^a = 89
    2 + 1^a + 1^a + d^a = 89
    2^a + d^a = 87

  • math (Reiny) -

    I don't know how to do

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