The particle wavelength of your lecturer in 3.091 on his way from the office to 10-250 (200 yards, 1 yard = 0.9144 m) has been determined to be 4.045 x 10 -36m. Taking his body weight to be 178 lbs (1 lb = 0.4536 kg), how long does it take him to get to his class? (answer in seconds)

wavelength = h/mv

Solve for v. Then
distance = rate x time
Substitute and solve for time.

pls the formula :)

thanks bob it worked!

can u help me KS

Hi, Menes. I an getting a very strange answer, which is incorrect. I must be using the wrong formula. Can you assist. Thanks.

Okay i am going to list down all the answers i got so far, please assist me in those which i left, if you have any:

1)156.675158119
2)5
3)90.1775147929
4)3s,3p,4s,3d,5s,5p,4f
10,2,14,6
5)-777
2.86e-10
6)8.88
dont know what part b is
7)O2, O2-2
8)tetrahedral,2,1,1,no,no
9)LiF don't know the reason
10)dont know part a
6.3e4
11)BN,AlAs, C,GaAs,GaP
12)
13)1.04e-3,p-type
14
15
16
17)Sn < Ge < Si
18
19) 6
20
21) B
22)1.8e-6
23)0.000258
24)
25
26
27
28)A is wrong, 3320, thermoplastic no covalent bonds
29
30
31
32)-0.0453
14.0453
33)4.77
10.76
1
34) hydrogen bond

Pls help me get the rest ones ASAP

Hi KS, Thanks. 6b) 3.22*10^5

You are welcome, thanks. I forgot to convert from KJ/mol to J/mol!

If you get anything else, pls do share on this page!

This is what I did with No. 12 Gallium Nitride.

A) I said No.
B) Wavelength = h*c/E_g = 6.626*10^-34 x 3*10^8/ 3.2 x 1.602 * 10^-19
= 0.388 *10^-6
This is a long shot. Maybe someone can pick up on it.

28 is A and D