Posted by **dreidel** on Wednesday, December 18, 2013 at 10:34pm.

To what interval I must we restrict the parameter t if the graph of the parametric equations

x=t+1

y = 2t^2 +1

for t in the set I

is identical to the graph of the parametric equations

x = 1+ sin s

y = 2- cos(2s)

for s in [0,pi)?

- precalculus -
**Steve**, Thursday, December 19, 2013 at 12:25am
it appears we need

1+t = 1+sin s,so

t = sin s

t must be in [0,1] if s is in [0,pi)

also,

2t^2+1 = 2-cos(2s)

2t^2+1 = 2 - (1-2sin^2 s)

2t^2+1 = 2sin^2 s + 1

same domain.

- precalculus -
**dreidel**, Thursday, December 19, 2013 at 6:05pm
Thx!

## Answer This Question

## Related Questions

- Precalculus - Let G be the graph of the parametric equations x=cos(4t)and y=sin(...
- Precalculus - Let G be the graph of the parametric equations x=cos(4t)and y=sin(...
- Math: Parametric Equations - Let G be the graph of the parametric equations x = ...
- Precalculus - Find the sum of all possible values of the constant k such that ...
- Precalculus - Find the sum of all possible values of the constant k such that ...
- Precalculus - The graph of the parametric equations x=cos(t), y=sin(t) meets the...
- Math: Parametric Equations - The graph of the parametric equations x=cos(t) y=...
- Math-Precalculus-Parametric Equations - Ellipses - The graph of the equation (x-...
- math - Graph x = y^2-6y+11 a. In function mode using two functions b. In ...
- Math (repost) - Graph x = y^2-6y+11 a. In function mode using two functions b. ...

More Related Questions