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Algebra 2

posted by on .

How do you solve this exponential equation using logarithms?

2*5^x=85

Do you start like this?

xlog2*5=log85

I don't know what to do after that.

  • Algebra 2 - ,

    I think I figured it out.
    85/2=42.5

    log5=log42.5

    log42.5/log5

    =2.330 to the third decimal

  • Algebra 2 - ,

    2^5x = 85
    Log2^5x = log85
    5xlog2 = log85
    Solve for x
    x = log85/5log2

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