Posted by **Steven** on Tuesday, December 17, 2013 at 5:23pm.

A student union wants to obtain a 90% confidence interval for the proportion of “full time” students who hold a part-time job for 20 hours or more per week. For this purpose, they want to interview a sample of full-time students. They want a margin of error to be at most 0.1, i.e., the length of the confidence interval should not exceed 0.2. What is the minimum number of full-time students they should interview?

• A researcher wants to determine the difference between the gestational period (period of pregnancy) for two groups of women, namely, those who had normal pregnancies (group A) and those who suffered from a certain complication during pregnancy known as preeclampsia (group B). The following data shows the gestational periods (in weeks) for a sample of 14 women from group A and of 13 women from group B.

Gestational periods for sample from group A: 40, 41, 38, 40, 40, 39, 39, 41, 41, 40, 40, 40, 39, 38

Gestational periods for sample from group B: 38, 30, 32, 42, 30, 38, 35, 32, 38, 39, 29, 29, 32

Find a 95% confidence interval for the difference between the gestational periods of group A and group B, i.e., group A mean minus group B mean. Assume that the variances of the two groups are equal. State any other assumptions you make.

Hint: This relates to confidence interval for

- statistics 3. -
**MathGuru**, Tuesday, December 17, 2013 at 6:26pm
Here are a few ideas to get you started.

First problem:

Use a formula to find sample size.

Here is one for proportions:

n = [(z-value)^2 * p * q]/E^2

... where n = sample size, z-value is 1.645 (90% confidence interval), p = .5 (when no value is stated), q = 1 - p, ^2 means squared, * means to multiply, and E = 0.1 listed in the problem.

Plug values into the formula and calculate n.

Second problem:

You will need to use a two-sample confidence interval formula. You will also need to calculate mean and standard deviation for both groups.

Here is one:

CI95 = (x1 − x2) ± z-value * √(s1^2/n1 + s2^2/n2)

(Note: * means to multiply)

x1 = mean A

x2 = mean B

z-value = 1.96

s1^2 = standard deviation A (squared)

s2^2 = standard deviation B (squared)

n1 = sample size A

n2 = sample size B

Plug the values into the formula and calculate the interval.

I'll let you take it from here.

## Answer This Question

## Related Questions

- statistics - A student union wants to obtain a 90% confidence interval for the ...
- MATH Statistics - A student union wants to obtain a 90% confidence interval for ...
- statistics 3. - A student union wants to obtain a 90% confidence interval for ...
- Statistics 3 - A student union wants to obtain a 90% confidence interval for the...
- statistics - The Office of Student Services at a large western state university ...
- STATISTICS - In a random sanple of 500 students, 80% say they have a part-time ...
- stats - In a random sample of 500 students, 80% say they have a part-time job. ...
- statistics - To determine how many hours per week freshmen college students ...
- Statistics - Professor York randomly surveyed 240 students at Oxnard University...
- Statistics - 28. A group of statistics students decided to conduct a survey at ...

More Related Questions