My math exam is coming up Friday and I need help!! Can you please guide me throgh the processes on the three questions? Thank you so much greatly apreciate it!!

Write the standard form of the equation of each line given the slipe and y-intercept.
1. Slope= -1/5, y-intercept=0

Write the slope intercept form of the equation of each line.
2. Y-3=-2(x+4)

Write the slope intercept form of the equation of the line thorough the given points.
3. Through: (1,-4) and (-5,-4)

My math assignment is already due last sartuday i need help please?

Of course! I'd be happy to help you with your math questions. Let's break down each question and go through the process step by step:

1. To write the standard form of the equation of a line given the slope and y-intercept, we use the formula: y = mx + b, where "m" represents the slope and "b" represents the y-intercept.

In this case, the slope is -1/5 and the y-intercept is 0. So, our equation becomes: y = (-1/5)x + 0. Simplifying, we get: y = (-1/5)x.

The standard form of this equation is: 1/5x + y = 0.

2. To write the slope-intercept form of the equation of a line, we use the formula: y = mx + b, where "m" represents the slope and "b" represents the y-intercept.

In the given equation, we already have it in the form of y - b = m(x - a), where "b" represents the y-intercept and "a" represents the x-coordinate of a point on the line.

Now, let's rearrange the equation to slope-intercept form:
y - 3 = -2(x + 4).

Distribute the -2 to both terms inside the parentheses:
y - 3 = -2x - 8.

Add 3 to both sides of the equation to isolate y:
y = -2x - 8 + 3.

Simplify:
y = -2x - 5.

So, the slope-intercept form of the equation is y = -2x - 5.

3. To find the slope-intercept form of the equation of a line passing through two given points, we use the formula: y - y1 = m(x - x1), where (x1, y1) represents one point on the line and "m" represents the slope.

In this case, we have the points (1, -4) and (-5, -4).

Let's calculate the slope:
m = (y2 - y1) / (x2 - x1).
m = (-4 - (-4)) / (-5 - 1).
m = 0 / (-6).
m = 0.

Since the slope is 0, the equation of the line will be y = -4 (no x-term as the slope is 0).

Therefore, the slope-intercept form is y = -4.

I hope this explanation helps! Good luck with your math exam on Friday. If you have any more questions, feel free to ask.

Wow, I must say, if you cannot do those questions, then you are certainly not ready for your math exam

1. if the y-intercept is 0, doesn't that mean the line goes through the origin or (0,0) ????
so in y = mx + b form ...
y = (-1/5)x
multiply by 5
5y = -x
standard form has both x and y terms on the left, constants on the right, so
x + 5y = 0

2. given:
y - 3 = -2x - 8
take the -3 to the other side ...
y = -2x - 5

3. slope = (-4 - (-4))/-5-1) = 0/-6 = 0
so you have a horizontal line !
look at the y values of your two points, both -4
As a matter of fact, your equation would simply be
y = -4