Solve for each of the variables:
3(x+3)/5 +y/2 + 2z = -1
x/3 + 5y-2/4 + z= 0
x - 2(y+1)/3 - 3z =-2
Clear fractions to get things easier to work with:
6(x+3)+5y+20z = -10
4x+60y-6+12z = 0
3x-2(y+1)-9z = -6
Clear parentheses and collect variables on the left to get
6x+5y+20z = -28
4x+60y+12z = 6
3x-2y-9z = -4
Now just solve by your favorite method to get some nasty fractions.
If, however, you are less careless with your parentheses, and the second equation is
x/3 + (5y-2)/4 + z= 0
then you get
(x,y,z) = (-3, 2, -1)
There are no parantheses in the second equation its just:
x/3 + 5y-2/4 + z =0
yes, but if it says
5y-2
-------
4
That means that the quantity (5y-2) is divided by 4.
If not, then go for the messy fractions.