Michael and mateo begin running around a circular track from the starting point at the same time. it takes Michael 48 seconds one lap around the track. it takes mateo 60 seconds to complete one lap around the track
how many minutes does it take before the two boys will meet at the starting point again?
how many laps will each boy have run by then?
The way he got the answer was to find the least common multiple for 48 seconds and 60 seconds which is 240 seconds then multiply 240 seconds x 2 because there are 2 boys (runners) which equals 480 seconds ÷ 60 sec (1 min) which is 8 mins. Hope this helps.
What about B?
What about B? Summer math can be hard😕
what does b mean
where did u get 480 from? the lcm is 240
can someone tell me about b
To determine how many minutes it takes for the two boys to meet at the starting point again, we need to find the least common multiple (LCM) of their lap times.
The lap time for Michael is 48 seconds, and the lap time for Mateo is 60 seconds.
To find the LCM of two numbers, we can use the formula LCM(a, b) = (a * b) / GCD(a, b), where GCD(a, b) represents the greatest common divisor of a and b.
In this case, we need to find the LCM of 48 and 60.
To find the GCD of two numbers, we can use the Euclidean algorithm. Let's find the GCD first:
GCD(48, 60):
- Divide 60 by 48: The quotient is 1 and the remainder is 12.
- Divide 48 by 12: The quotient is 4 and there is no remainder.
- The GCD(48, 60) is the last non-zero remainder, which is 12.
Now, we can find the LCM:
LCM(48, 60) = (48 * 60) / GCD(48, 60)
= (2880) / 12
= 240.
Therefore, it will take 240 seconds for the two boys to meet at the starting point again.
To convert seconds to minutes, we divide by 60:
240 seconds / 60 = 4 minutes.
So, it will take 4 minutes for Michael and Mateo to meet at the starting point again.
To find the number of laps each boy will have run by then, we divide the total time taken by their respective lap times.
For Michael:
4 minutes * (60 seconds / 48 seconds) = 5 laps (rounded down from 5.0 laps)
For Mateo:
4 minutes * (60 seconds / 60 seconds) = 4 laps.
Therefore, Michael will have completed 5 laps and Mateo will have completed 4 laps by the time they meet at the starting point again.
no
No
LCM(48,60) = 240
so, they meet again in 480 seconds, or 8 minutes.
I guess you can figure out the rest, no?