A 1.13 kg skateboard is coasting along the pavement at a speed of 4.28 m/s when a 0.93 kg cat drops from a tree vertically downward onto the skateboard. What is the speed of the skateboard-cat combination?
m₁v=(m₁+m₂)u
u= m₁v/(m₁+m₂)=
=1.3•4.28/(1.3+0.93)=