Posted by jc on Thursday, December 12, 2013 at 7:05pm.
3x5y=6
6x+5y=34
how do i solve this using elimination?

algebra  Anonymous, Thursday, December 12, 2013 at 7:13pm
First you add the equations.
5y and 5y cross each out so you are left with 3x=40
X= 40/3
Plug x back into one of the equations
3x5y=6
3(40/3)5y=6
405y=6
5y= 34
Y=34/5

algebra  Anonymous, Thursday, December 12, 2013 at 7:15pm
Correction: It should be positive 405y=6
So 5y=46
Y=46/5
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