A toy car runs off the edge of a table that is 1.225 meters high. If the car lands 0.400 meters from of the table,

a. How long does it take for the car to fall?

b. What is the horizontal velocity of the car?

To solve this problem, we can use the equations of motion.

Given:
Initial vertical position (s0) = 1.225 meters
Vertical displacement (Δs) = -1.225 meters (as the car falls down)
Vertical acceleration (a) = 9.8 m/s^2 (acceleration due to gravity)
Horizontal displacement (Δx) = 0.400 meters

a. To determine the time it takes for the car to fall, we can use the second equation of motion:
Δs = s0 + v0t + 0.5at^2

Since the initial vertical velocity (v0) is zero (assuming the car starts from rest), the equation simplifies to:
Δs = 0.5at^2

Substituting the given values:
-1.225 = 0.5 * 9.8 * t^2

Solving for t:
1.225 = 4.9t^2
t^2 = 1.225 / 4.9
t^2 = 0.25
t = √0.25
t = 0.5 seconds

Therefore, it takes 0.5 seconds for the car to fall off the table.

b. To find the horizontal velocity of the car, we can use the equation:
v = Δx / t

Substituting the given values:
v = 0.400 / 0.5
v = 0.8 m/s

Therefore, the horizontal velocity of the car is 0.8 m/s.

To find the answers to these questions, we can use the equations of motion for an object in free fall.

a. To calculate the time it takes for the car to fall, we can use the equation:

h = (1/2) * g * t^2

Where:
h = height from which the car falls (1.225 meters)
g = acceleration due to gravity (approximately 9.8 m/s^2)
t = time taken for the car to fall (unknown)

Rearranging the equation to solve for t:

t^2 = (2 * h) / g
t = sqrt((2 * h) / g)

Substituting the given values:

t = sqrt((2 * 1.225 meters) / 9.8 m/s^2)
t = sqrt(0.25 s^2)
t ≈ 0.50 seconds

Therefore, it takes approximately 0.50 seconds for the car to fall.

b. The horizontal velocity of the car remains constant throughout the fall because there are no horizontal forces acting on it.

To find the horizontal velocity, we need to know the horizontal distance the car travels. Given that the car lands 0.400 meters from the edge of the table, we can assume its horizontal velocity is constant.

Therefore, the horizontal velocity of the car is simply the horizontal distance divided by the time taken to fall:

Horizontal velocity = Distance / Time
Horizontal velocity = 0.400 meters / 0.50 seconds
Horizontal velocity = 0.8 m/s

The horizontal velocity of the car is 0.8 m/s.

A..225=4.9*T^2 , so T= 0.5s

B.V0= 0.4/0.5=0.8m/s

Does this help?:)