Assume that the rate of population growth of ants is given by the equation:
dP/dt=.1P(1 - P/730)-(129000/7300)
a. If P(0)=150, what happens to P as t gets very large?
b. If P(0)=800, what happens to P as t gets very large?
c. If P(0)=800, what happens to dP/dt as t gets very large?
d. What are the equilibrium solutions?
Since P(x) is a cubic with negative leading coefficient, it becomes more and more negative. However, I'm not sure what a negative population means.
equilibrium means dP/dt = 0, so
t = 300 or 430
Hard to imagine a quadratic rate of growth. Usually it some kind of negative exponential.