Posted by **tiffany** on Wednesday, December 11, 2013 at 6:35pm.

Find the area of the indicated region. We suggest you graph the curves to check whether one is above the other or whether they cross, and that you use technology to check your answer.

Enclosed by y = x^2 − 4x + 1 and y = −x^2 + 4x − 5

- Calculus -
**Steve**, Wednesday, December 11, 2013 at 6:44pm
the curves intersect at x=1,3 so the area is

∫[1,3] (−x^2 + 4x − 5 )-(x^2 − 4x + 1) dx

= ∫[1,3] -2x^2 + 8x - 6 dx

= -2/3 x^3 + 4x^2 - 6x [1,3]

= 8/3

- Calculus -
**tiffany**, Wednesday, December 11, 2013 at 6:56pm
thank you so much

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