Posted by Anonymous on Tuesday, December 10, 2013 at 8:47pm.
Logx16=2 how do you solve this?

Help please!! For precalc  Anonymous, Tuesday, December 10, 2013 at 8:50pm
the first one is simple, logx16=2 .... x becomes the base and the 2 becomes the exponent there fore x^2=16 and this becomes basic when solving for , put both x^2 and 16 under a radical and x=4

Help please!! For precalc  Anonymous, Tuesday, December 10, 2013 at 8:56pm
The answer I think is wrong

Help please!! For precalc  Anonymous, Tuesday, December 10, 2013 at 8:59pm
A negative cant cHange to a positive without doing anything
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