Posted by Anonymous on .
Logx16=2 how do you solve this?

Help please!! For precalc 
Anonymous,
the first one is simple, logx16=2 .... x becomes the base and the 2 becomes the exponent there fore x^2=16 and this becomes basic when solving for , put both x^2 and 16 under a radical and x=4

Help please!! For precalc 
Anonymous,
The answer I think is wrong

Help please!! For precalc 
Anonymous,
A negative cant cHange to a positive without doing anything