Friday

December 19, 2014

December 19, 2014

Posted by **Raj** on Tuesday, December 10, 2013 at 8:39pm.

x(dy/dx) + 1 = y^2

y(1)=0

I tried using bernoulli and it didn't quite work.

- Calculus -
**Steve**, Tuesday, December 10, 2013 at 11:33pmxy' + 1 = y^2

xy' = y^2-1

y' = (y^2-1)/x

dy/(y^2-1) = dx/x

arctanh(y) = log(x)

or,

log (1-y)/(1+y) = 2log(x)+c

and you can massage that into exponentials and wind up with

y = 1-e^(2cx^2) / 1+e^(2cx^2)

**Answer this Question**

**Related Questions**

Differential Equations - x dy/dx + y = 1/y^2, solve using bernoulli's equation. ...

Calculus-HELP!!!! - Show that the function y=c_1 e^x cos(x)+ c_2 e^x sin(x) ...

Differential Equation - Solve the following initial-value problem: y"+6y'+5y=0...

CALCULUS - Using separation of variables technique, solve the following ...

calculus - how do you solve the initial value problem by using separation of ...

calculus - how do you solve the initial value problem by using separation of ...

calculus - how do you solve the initial value problem by using separation of ...

Differential Equations - Solve the seperable differential equation for U. du/dt...

Differential Equations - Solve dy/dx = y/(2y-x) using rational substitution (...

Calculus II - Solve the initial value problem using Taylor Series and the ...