Sunday

April 20, 2014

April 20, 2014

Posted by **Raj** on Tuesday, December 10, 2013 at 8:39pm.

x(dy/dx) + 1 = y^2

y(1)=0

I tried using bernoulli and it didn't quite work.

- Calculus -
**Steve**, Tuesday, December 10, 2013 at 11:33pmxy' + 1 = y^2

xy' = y^2-1

y' = (y^2-1)/x

dy/(y^2-1) = dx/x

arctanh(y) = log(x)

or,

log (1-y)/(1+y) = 2log(x)+c

and you can massage that into exponentials and wind up with

y = 1-e^(2cx^2) / 1+e^(2cx^2)

**Related Questions**

Calculus - Seperable Equations - Solve the separable differential equation (dy/...

calculus - Can you give me a good website on the topic, slope fields and ...

calculus - solve the initial value problems: 1- dq/dz = 2 + sinz, q(0)=5 2-dy/...

Math - Find the specific solution for the following differential equations: a) (...

calculus - How do you solve the initial value problem? (dy/dx)-2y+4=0, y(1)=4

calculus - solve the initial value problem by separation of variables dy/dx=y^(2...

Calculus - How do you us implicit differentiation to solve x( y + 2 )^5 = 8 x( y...

calculus - how do you solve the initial value problem by separation of variables...

calculus - solve the initial value problem by separation of variables dy/dx=-x^...

calculus - solve the initial value problem by separation of variables dy/dx=-x^...