What will be the concentration of the solution formed when 5.72mL of 8.50M HCl is diluted to 250mL?

8.50M x *(5.72 mL/250 mL) = ?M

.194

To find the concentration of the solution after dilution, we can use the equation:

C1V1 = C2V2

Where:
C1 = initial concentration of the solution (in this case, 8.50M)
V1 = initial volume of the solution (in this case, 5.72mL)
C2 = final concentration of the solution (what we are trying to find)
V2 = final volume of the solution (in this case, 250mL)

Let's substitute the known values into the equation:

(8.50M)(5.72mL) = C2(250mL)

To solve for C2, we divide both sides of the equation by 250mL:

C2 = (8.50M)(5.72mL) / 250mL

C2 = 0.19448M

Therefore, the concentration of the solution formed after dilution is approximately 0.19448M.