Posted by Please, help me! on Monday, December 9, 2013 at 1:24pm.
1) (3,3)
2) y = 2x
y = .50x + 16
3) -x/5 = 12
X = -60
Vertical line so slope is undefined
4. 2/5 = y/12
y = 12(2/5) = 24/5
y = 24/5
Horizontal line so slope is 0
5) 6x + 12 = -2x -20
8x = -32
x = -4
6) 8x + 4 > 28
8x > 24
x > 3
7) 5x + 24 <= 15
5x >= -9
x <= -9/5
I usually pick values of x near the origin of the x-y grid
e.g. x = 0 , ± 1, ± 2 , ±3
since you know it is a straight line, you really only need 2 points.
But, I usually take a third point as a check:
x=0 , y1 - 0 , y2 = 6
x = 1 y1 = 1 , y2 = -1+6 = 5
x = 4, y1 = 4, y2 = -4+6 = 2
so I got 3 points for each of the lines
line1 -- (0,0), (1,1) , (4,4)
line2 -- (0,6) , (1 , 5) and (4,2)
notice had I picked x = 3
line1 : point (3,3)
line 2 : point is (3,3) , well , what do you know ?!
2 a) Don't know what you mean by the "situation"
Was there a situation for him to buy roses for Valentines ?
Where does the delivery charge come in ?
In the selling of them or when they bought tem?
#3 good
#4 good
#5
6x + 12 = -2x - 20
8x = -32
x= -4
#6 good
#7
multiply each term by 40 , the LCD, to clear the fractions
5x + 24 ≤ 15
5x ≤ -9
x ≤ -9/5
2. b. It represents, how many carnations needed to be carnations: 11
c . No because the solution is not a sold to break even. Total number of carnations.