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March 31, 2015

Posted by **Hil** on Monday, December 9, 2013 at 6:34am.

(a) What is the speed V of the rocket after a burn time of 140 seconds (in m/s)?

(b) What is the instantaneous acceleration a of the rocket at time 140.0 seconds after start of the engines (in m/s^20)? I have tried to solve, but not been successful. Thanks for your help.

- physicS IMP PLS -
**Hil**, Monday, December 9, 2013 at 6:57amI have tried to solve this problem the following way:

5% mass is burned in 280s.

1.5 km/s = 1500 m/s

u=fuel speed m/s

Solution:

V= u*ln(1/(1-p))

1500*ln(1/0.950) = 76.9399416 m/s

a= V/t = 76.9399416/280 = 0.274785506 m/s^2

What is confusing to me what is the speed after 140s and instantaneous acceleration a 140 s after the start of the engines. Thanks for your help.

- physicS IMP PLS -
**anonymus**, Monday, December 9, 2013 at 9:21amTHE instantaenous acc is just the acceleration of the rocket

- physicS IMP PLS -
**Hil**, Monday, December 9, 2013 at 9:27amHi Anonymus, So my question is V= 76.939416 m/s and a=0.2747 m/s^2 correct. Is the other information just trying to through us off? Thanks.

- physicS IMP PLS -
**Anonymous**, Monday, December 9, 2013 at 9:43amdo you know how to solve the ruler question?

- physicS IMP PLS -
**Greco**, Monday, December 9, 2013 at 10:03amno it is wrong!!! he ask you "What is the speed V of the rocket after a burn time of 140 seconds (in m/s)? " that is the half of time and half of % . so ..

1500*ln(1/0.750) = 37.91 m/s

a=v/t=37.91/140=0.27

- physicS IMP PLS -
**Greco**, Monday, December 9, 2013 at 10:05amsorr that waw

1500*ln(1/0.9750) = 37.91 m/s

- physicS IMP PLS -
**Hil**, Monday, December 9, 2013 at 10:28amHi Anonymous, I tried that problem and was unsuccessful. My answer was 8 radians. I knew it was wrong. I put that off to the side. I am just trying to get a passing grade. Thanks for your help. If I learn any thing I will let you know. Also Thanks Greco and everyone who was kind enough to help me out.

- physicS IMP PLS -
**Greco**, Monday, December 9, 2013 at 10:31amalways here Hill...if you can help with ruler problem it will pe magnificent

- physicS IMP PLS -
**Hil**, Monday, December 9, 2013 at 11:03amHi, Greco. To be honest Questions 1 and the ruler are by far the most difficult for me. when I started the test I knew I was in trouble. I saw this approach:

Apply the conservation of energy

U= m*g*h cm

Ek = m*g* (L/2)+0

l=1/3*m*L

Einitial= m*g*(L/2)+0

Efinal= m*g*(2/L)cos30+1/2*L*w^2

Solve for Einitial = Efinal -> w =

Maybe you saw this. I hope it helps.

- physicS IMP PLS -
**Greco**, Monday, December 9, 2013 at 2:18pmi know this ,i already done it.thx for the efford!

- physicS IMP PLS -
**Greco**, Monday, December 9, 2013 at 3:15pmI=1/3*m*L^2

Eini= mg(L/2) + 0

Efin= mg(L/2)cos30 + 1/2*I*w^2

Eini=Efin ->

w=sqrt(3*g (1-cos(theta))/L)

b)

alpha=3*mg/2*sin(theta)/L

ax = -L/2*sin(theta) w^2 + L/2*cos(theta) alpha

Fx=m*ax

Fy=m*g*cos(theta)-m*w^2*(L/2)

c)

cos(theta)=2/3

theta=48.19

- physicS IMP PLS -
**socorro**, Monday, December 9, 2013 at 5:09pmI=1/3*m*L*L?

- physicS IMP PLS -
**Anon**, Monday, December 9, 2013 at 5:56pm@Greco I tried it and it workrd for a and c and for Fy but Fx was wrong!why did you use alpha? please help with this question!

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