posted by b on .
In the combustion reaction of 149g of propane(C3H8) with excess oxygen, what volume of carbon dioxide(CO2) is produced at STP?
(note: balance the reaction first)
C3H8 + O2 3CO2 + H2O
C3H8 + 5O2 3CO2 + 4H2O
mols C3H8 = grams/molar mass
Using the coefficients in the balanced equation, convert mols C2H8 to mols CO2.
Now convert mols CO2 to L remembering that 1 mol occupies 22.4 L OR you can use PV = nRT and solve for V in L../