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November 25, 2014

November 25, 2014

Posted by **sarah** on Sunday, December 8, 2013 at 3:29pm.

For example, 47, 41, 32, 53, 57. First you find the mean, which is 46 and then subtract it with each number in the set so you get 1, -5, -14, 7, 11. then you square each # to get 1, 25, 196, 49, 121. then add all the numbers to get 392 & you do 392/n-1 (n being how many #s there are in the set) so 392/5-1 = 98 then you square root 98 & the standard deviation is 9.9.

For 8, 5, 12, 8, 9, 15, 21, 16, 3 the standard deviation is 5.73973 but when i tried the process i get a completely different answer. First the i found the mean, which is 10.77777778. (97/9) but after this i started messing up, help?

- math -
**Kuai**, Sunday, December 8, 2013 at 4:06pmmean = 97/9 = 10.78

Sd = sqrt ((x -mean)^2/(n-1)) = 5.7397

correct

- math -
**sarah**, Sunday, December 8, 2013 at 4:21pmhow do you do it the way i showed above? because our teacher doesn't want us to use the formula

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