Tuesday

September 16, 2014

September 16, 2014

Posted by **Lily** on Saturday, December 7, 2013 at 8:40am.

- Math -
**Reiny**, Saturday, December 7, 2013 at 11:11amC must be the right angle.

You have 3 similar triangle, the original and 2 smaller ones

let the altitude be h

2/h = h/16

h^2 = 32

h = √32

in the smaller right-angled triangle

h^2 + 2^2 = BC^2

BC^2 = 32 + 4 = 36

BC = 6

In the other right-angled triangle:

AC^2 = h^2 + 16^2

= 32 + 256 = 288

AC = √288 = 12√2

perimeter of ABC = 6 + 12√2 + 18

= 24 + 12√2

**Answer this Question**

**Related Questions**

Math - the altitude, AD, to the hypotenuse BC of right triangle ABC divides the ...

Geometry - The altitude to the hypotenuse of a right triangle ABC divides the ...

Geometry - The altitude of the hypotenuse of a right triangle divides the ...

geometry - The altitude upon the hypotenuse of a right triangle divides the ...

math - The legs of a right triangle are 3 and 4 units long. Find the lengths, to...

Geometry - If the length of the altitude of the hypotenuse of a right triangle ...

Geometry - Right triangle ABC has one leg of length 12 in and a hypotenuse of ...

Geometry - In right triangle ABC, the median to the hypotenuse has length 15 ...

math - I have 14 questions and I was wondering if someone could check my answers...

Geometry - In the diagram below, the length of the legs AC and BC of right ...