Wednesday

March 4, 2015

March 4, 2015

Posted by **Amanda** on Saturday, December 7, 2013 at 3:35am.

40x^5-56x^4+24x^3 divided by -8x^2

- algebra -
**Steve**, Saturday, December 7, 2013 at 5:33amby dividing each term by -8 and by x^2:

-5x^3+7x^2-3x

**Answer this Question**

**Related Questions**

algebra - 40x^8-56x^4+24x divided by 8x Is this correct? 5x^7-7x^3+3

Math help - How would you solve these systems by elimination? I'm in desperate ...

algebra - Did I do this problem the correct way if so is there a shorter way to ...

algebra - Divide 48x^9-24x^3=40x 8x

math - 56x(3)y(5)-40x(2)y(6)+8x(2)y(3)

math - 56x^3y^5-40x^2y^6+8x^2y^3

alg2 check? - solve 3(8x-2)=46-2(12x+1) 24x-6=46-24x+2 24x-6=48-24x 48x-6=48 48x...

alg - Which of the following is equivalent to the rational number [3x / 4x]? a) ...

algebra 2 - find all the zeroes of: x^5-3x^4-24x^3-72x^2-25x+75=0 5x^5-20x^4-40x...

math - 24x^3-40x^2+3x-5