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February 28, 2015

February 28, 2015

Posted by **jeanie** on Saturday, December 7, 2013 at 12:07am.

I got 22.5 is that correct?

- calculus -
**Reiny**, Saturday, December 7, 2013 at 12:22amThe function crosses the origin

so I see it as

A = ∫ x(x^2+16)^(1/2) dx from 0 to 3

= [ (1/3)(x^2+16)^(3/2) ] from 0 to 3

= (1/3)(25)^(3/2) - 0

= (1/3)(125)

= 125/3

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