Complete the following fission reaction 1n0 + 235U92 → 131Sn50 + ? + 2 1n0 + energy

103 Mo 42

To complete the fission reaction, we need to determine the missing product. In a nuclear fission reaction, the neutron (symbolized as 1n0) bombards the uranium-235 isotope (symbolized as 235U92), resulting in the splitting of the uranium nucleus. This splitting produces two smaller nuclei, along with additional neutrons and energy.

To find the missing product, we can consider the conservation of atomic numbers (protons) and mass numbers (total number of protons and neutrons) on each side of the reaction.

On the left side of the reaction, we have:
Atomic number (protons) = 0
Mass number (protons + neutrons) = 1

On the right side of the reaction, we have:
Atomic number (protons) = 50 (for tin, Sn)
Mass number (protons + neutrons) = 131

Since the atomic number of the product is 50, we can identify the element as tin (Sn). The mass number of 131 indicates the total protons and neutrons in the nucleus of the tin atom.

Therefore, to complete the fission reaction, the missing product is 131Sn50 (tin-131).

Note: The question also mentions the production of two neutrons and energy as additional products of the fission reaction.