Algebra
posted by Anonymous on .
I have an assignment to write an equation to pointslope form, then to standard form, and then to slopeintercept form. I have used the points (2,1) or (1,2), but I used (2,1).
Now, I have the pointslope form of y + 1= 1(x + 2) and the standard form of y – 1x = 1. When I convert into slopeintercept form, I am getting the slope as 1, which is the problem. Could someone please tell me where I am going wrong?

Actually, the slope is not 1, but the yintercept comes up as 1.

your slope is correct as +1
your equation of
y+1 = 1(x+2) is also correct
then y+1 = x+2
y = x+1 > slopeyintercept form
yx = 1
x  y = 1 > standard form ( I multiplied each term by 1) 
So, how did you multiply the terms by 1?

And how do you rewrite x  y = 1 into slopeintercept form?

in standard form we usually lead with the x term with a positive coefficient, so I wanted a +x as my first term, it was x .
to change a standard form to slope yintercept form usually takes 2 steps:
1. move all terms except the y term to the right
e.g.
4x  5y = 8 ≥ 5y = 4x + 8
2. divide each term by the coefficient of the y term
5y = 4x + 8 > y = (4/5)x + 8/5
y = (4/5)x  8/5 , just an example, has nothing to do with your question
apply those 2 steps to your question.