Posted by Vaughn Murray on Thursday, December 5, 2013 at 12:44am.
How do I find the excluded value for
m^28+16/ 5m^2+ m

Math  Steve, Thursday, December 5, 2013 at 6:07am
the expression is undefined when the denominator is zero, because division by zero is undefined.
5m^2+m = m(5m+1), so it is zero for m = 0 or 1/5
even ignoring the typo in the numerator.