What is the osmotic pressure in atmospheres of a 15% sucrose solution at a temperature of 25 degrees celcius
To find the osmotic pressure in atmospheres of a 15% sucrose solution at a temperature of 25 degrees Celsius, you will need some information and apply the formula for osmotic pressure.
Here are the steps:
Step 1: Convert the temperature from Celsius to Kelvin.
- To convert Celsius to Kelvin, you add 273.15 to the Celsius value.
- In this case, 25 degrees Celsius + 273.15 = 298.15 Kelvin.
Step 2: Determine the molar concentration of the 15% sucrose solution.
- You have a 15% sucrose solution, meaning that 15 grams of sucrose is dissolved in 100 grams of solution.
- Convert grams to moles by dividing by the molar mass of sucrose, which is 342.3 g/mol.
- 15 grams / 342.3 g/mol = 0.0438 mol.
- The molar concentration is the moles of solute divided by the volume of the solution in liters. Since the volume is not given, we assume it to be 1 liter.
- Molar concentration = 0.0438 mol / 1 L = 0.0438 M (Molar).
Step 3: Calculate the osmotic pressure using the formula:
- Osmotic pressure (in atmospheres) = molar concentration (in M) * ideal gas constant (0.0821 L·atm/(K·mol)) * temperature (in Kelvin)
- Osmotic pressure = 0.0438 M * 0.0821 L·atm/(K·mol) * 298.15 K.
- Osmotic pressure = 1.0971 atm.
Therefore, the osmotic pressure in atmospheres of a 15% sucrose solution at a temperature of 25 degrees Celsius is approximately 1.0971 atm.