a 5.82 kg piece of copper metal is heated from 21.5c to 328.3. calculate the head absorbed. Assuming it doesn't undergo a phase change.
Cu specific heat 0.385 j/g*c
Bob Pursley answered this below.
q = mass in grams x specific heat x (Tfinal-Tinitial)
Substitute and solve for q.
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To calculate the heat absorbed by the copper metal, you can use the formula:
Q = m * c * ΔT
Where:
Q is the heat absorbed,
m is the mass of the copper metal (in grams),
c is the specific heat capacity of copper (in J/g°C),
ΔT is the change in temperature (in °C).
Given:
Mass of copper metal (m) = 5.82 kg = 5820 g
Specific heat capacity of copper (c) = 0.385 J/g°C
Initial temperature (T1) = 21.5°C
Final temperature (T2) = 328.3°C
First, let's calculate the change in temperature (ΔT):
ΔT = T2 - T1
ΔT = 328.3°C - 21.5°C
ΔT = 306.8°C
Now, we can substitute the values into the formula to calculate the heat absorbed (Q):
Q = (mass) * (specific heat capacity) * (change in temperature)
Q = (5820 g) * (0.385 J/g°C) * (306.8°C)
Q = 680,231.2 J
The heat absorbed by the copper metal is 680,231.2 J.