Thursday

January 29, 2015

January 29, 2015

Posted by **Roni** on Wednesday, December 4, 2013 at 2:27pm.

y = 16 x and y = 2 x^2 about y =0

Find the volume of the solid obtained by rotating the region bounded about the x-axis by y=4x^2, x =1, and y = 0

Find the volume of the solid generated by rotating the region bounded by

y = \sin^2(x) and y = 0

between 0 and pi about the x-axis

- Calculus volume stuff -
**Steve**, Wednesday, December 4, 2013 at 2:42pmwashers: v=∫[0,8] π(R^2-r^2) dx

where R=16x and r=2x^2

= 2621454/15 π

shells: v=∫[0,128] 2πrh dy

where r=y and h=√(y/2)-y/16

= 2621454/15 π

Can you set up the other integrals?

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