in a thermonuclear device, the pressure of 0.050 liters of gas within the bomb casing reaches 4000000 atm. when the bomb casing is destroyed by the explosion, the gas is released into the atmosphere where it reaches a pressure of 1.00 atm. what is the volume of the gas after the explosion.
To calculate the volume of the gas after the explosion, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law equation: P1 * V1 = P2 * V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
In this case, we are given:
Initial pressure (P1) = 4,000,000 atm
Initial volume (V1) = 0.050 liters
Final pressure (P2) = 1.00 atm
Final volume (V2) = ?
Substituting these values into Boyle's Law equation:
(4,000,000 atm) * (0.050 liters) = (1.00 atm) * (V2)
Expanding the equation:
200,000 liters * atm = V2
Therefore, the volume of the gas after the explosion is 200,000 liters.