Posted by **Anonymous** on Sunday, December 1, 2013 at 11:27pm.

I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!

((3^3)^(cosx+2/3sinx))^2cosx+3sinx all divided by ((3^sinx)^13)^cosx = x

- Math -
**Reiny**, Sunday, December 1, 2013 at 11:49pm
I do not follow your order of exponents

You will have to be much more specific by using brackets

e.g.

2^3^4

done on my calculator by punching it in that way

gives me 4096

(The calculator appears to evaluate from left to right and simply does (2^3)^4 = 2^12= 4096

But, what about

(2^(3^{^4})

= 2^81

= huge !

on calculator , enter

2

y^{x}

(

3

y^{x}

4

)

=

to one humongous number (2.41... x 10^24)

Please clean up your expression

## Answer this Question

## Related Questions

- Pre Calculus - Having trouble verifying this identity... cscxtanx + secx= 2cosx ...
- Calculus - If y=3/(sinx+cosx) , find dy/dx A. 3sinx-3cosx B. 3/(sinx+cosx)^2 C...
- math - tanx+secx=2cosx (sinx/cosx)+ (1/cosx)=2cosx (sinx+1)/cosx =2cosx ...
- Pre-Calc - Trigonometric Identities Prove: (tanx + secx -1)/(tanx - secx + 1)= ...
- Trig........ - I need to prove that the following is true. Thanks (cosx / 1-sinx...
- Trigonometry Check - Simplify #3: [cosx-sin(90-x)sinx]/[cosx-cos(180-x)tanx] = [...
- Trig - prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= ...
- Math - Verify the identity . (cscX-cotX)^2=1-cosX/1+cosX _______ sorry i cant ...
- Math - Pre- Clac - Prove that each of these equations is an identity. A) (1 + ...
- Pre-Cal - Use the fundamental identities to simplify the expression. csc Q / sec...