Posted by **Anonymous** on Sunday, December 1, 2013 at 11:27pm.

I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!

((3^3)^(cosx+2/3sinx))^2cosx+3sinx all divided by ((3^sinx)^13)^cosx = x

- Math -
**Reiny**, Sunday, December 1, 2013 at 11:49pm
I do not follow your order of exponents

You will have to be much more specific by using brackets

e.g.

2^3^4

done on my calculator by punching it in that way

gives me 4096

(The calculator appears to evaluate from left to right and simply does (2^3)^4 = 2^12= 4096

But, what about

(2^(3^{^4})

= 2^81

= huge !

on calculator , enter

2

y^{x}

(

3

y^{x}

4

)

=

to one humongous number (2.41... x 10^24)

Please clean up your expression

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