posted by Anonymous .
I am having trouble with a pre-cal problem. If you could explain how to do it that would be great!
((3^3)^(cosx+2/3sinx))^2cosx+3sinx all divided by ((3^sinx)^13)^cosx = x
I do not follow your order of exponents
You will have to be much more specific by using brackets
done on my calculator by punching it in that way
gives me 4096
(The calculator appears to evaluate from left to right and simply does (2^3)^4 = 2^12= 4096
But, what about
= huge !
on calculator , enter
to one humongous number (2.41... x 10^24)
Please clean up your expression