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physics

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a baseball is popped straight up. the ball leaves the bat moving at 37.8 m/s. at what time is the ball 20 m above the ground?

  • physics - ,

    See your previous post: Sun,12-1-13,10:34 PM.

  • physics - ,

    h = Vo*t + 0.5g*t^2 = 20
    37.8t _ 4.9t^2 = 20
    -4.9t^2 + 37.8t - 20 = 0
    Use Quadratic Formula and get:
    t = 0.571, and 7.14 s.

    So, when the ball is rising; it reaches
    20 m in 0.571 s. When it is falling, it
    reaches 20 m in 7.14 s.

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