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6.01-L cylinder contains 1.25 mol of gas A and 4.54 mol of gas B, at a temperature of 32.8 °C. Calculate the partial pressure of each gas in the cylinder. Assume ideal gas I have work this question three time and can not get the rt answer

  • chem - ,

    PV = nRT
    p = nRT/V
    pA = 1.25*0.08206*(273.2 + 32.8)/6.01 = 5.22

    pB = same thing.

    When you have a problem like this it is better for you to show your work so we can find the error. Otherwise, we're shooting in the dark. It's easier for us to find the error than it is for us to type the entire problem, especially if you had more than one error.

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