If point A is (2,4) and point B is (3,2) and slope is -2 what would the equation be in standard form?
Use the formula
y -y1 = m(x-x1)
You can use either point and the slope.
y - 4 = -2(x-2)
y-4 = -2x + 4
y = -2x + 8
Now this is in y=mx+ b form
the question wants standard form. Can you finish from here?
No I don't know how to put this one in standard form!!
To find the equation of a line in standard form, we will use the point-slope form equation and then convert it to standard form.
Point-slope form equation:
y - y₁ = m(x - x₁)
where
m = slope of the line
(x₁, y₁) = coordinates of a point on the line
Given:
Point A: (2,4)
Point B: (3,2)
Slope (m) = -2
Let's use point A (2,4) and the given slope (-2) to find the equation in point-slope form:
y - 4 = -2(x - 2)
Now, let's simplify the equation:
y - 4 = -2x + 4
Next, let's rearrange the equation to get it into standard form (Ax + By = C):
2x + y = 8
So, the equation of the line in standard form is 2x + y = 8.