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March 2, 2015

March 2, 2015

Posted by **Anonymous** on Sunday, December 1, 2013 at 8:32pm.

What would the equation be in standard form?

- MATH -
**Joe**, Sunday, December 1, 2013 at 8:56pmy -y1 = m(x-x1)

Use either point...

y-3 = -1(x+8

y-3= -1x -8

y = -x -5

Now, change to standard from

to find the x- intercept.. let y =0 and solve for x.

to find the y- intercept, let x = 0 and solve for y.

- MATH -
**Reiny**, Sunday, December 1, 2013 at 8:57pmHenry had done this same question for you here

http://www.jiskha.com/display.cgi?id=1385944773

why did you repost it?

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