If point A is (-8,3) and point B is (-6,1) and the slope is -1 what would the x and y intercepts be?
y=mx+b
3=-1*-8 + b
b=3-8 =-5 that is the y intercept
What would the x intercept be?
To find the x-intercept and y-intercept, we need to know the equation of the line that passes through points A(-8, 3) and B(-6, 1). The equation of a straight line can be written in slope-intercept form as y = mx + b, where m represents the slope, and b represents the y-intercept.
Given that the slope (m) is -1, we can write the equation as y = -x + b.
To find b, we can substitute one of the points into the equation and solve for b. Let's use the coordinates of point A (-8, 3):
3 = -(-8) + b
3 = 8 + b
b = -5
So, the equation of the line passing through points A and B is y = -x - 5.
To find the x-intercept, we set y equal to zero in the equation and solve for x:
0 = -x - 5
x + 5 = 0
x = -5
The x-intercept is -5.
To find the y-intercept, we set x equal to zero in the equation and solve for y:
y = -0 - 5
y = -5
The y-intercept is -5.
Therefore, the x-intercept is -5, and the y-intercept is -5.