Posted by **Terri** on Saturday, November 30, 2013 at 4:40pm.

A trainee is hired by a computer manufacturing company to learn to test a particular part of a personal computer after it comes off the assembly line. The learning curve for an average trainee is given by N=200/4+21e^-0.1t

How many computers can a trainee be test after 2 days of training? So it would be N=200/4+21e^0.2

How do you compute 21e^-0.2

- PreCal - repost -
**Damon**, Saturday, November 30, 2013 at 4:49pm
N = 200 / ( 4 + 21 e^-.1t)

I think may be what you mean

- PreCal - repost -
**Damon**, Saturday, November 30, 2013 at 4:51pm
e^-.2 = 1/e^.2 = 1/1.2214= .8187

- PreCal - repost -
**Damon**, Saturday, November 30, 2013 at 4:52pm
so

N = 200 /( 4 +21*.8187)

= 9.44

- PreCal - repost -
**Damon**, Saturday, November 30, 2013 at 4:56pm
Note that as time becomes large, N becomes 200/4 or 50 so no matter how long you train, you will never test more than 50 a day.

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