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February 1, 2015

February 1, 2015

Posted by **Paran** on Friday, November 29, 2013 at 12:41pm.

- math -
**Reiny**, Friday, November 29, 2013 at 3:23pmIn any reciprocal function or rational function, the possibility exists that the denominator could be zero.

This would make the expression undefined, since we cannot divide by zero.

So set the denominator equal to zero, solve for the variable, and the solution becomes the restriction for your function

e.g. y = 5x/(x^ - 9)

solve x^2 - 9 = 0

x = ± 3

So the restriction is that x ≠ ± 3

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