Greeting All, please assist with the below. Thanks.

The spectral power density of a solar simulator is given by:
P(λ)=7.5∗1015λ−2.25∗109 [Wm^-2m^-1] for 300nm<λ<500nm

P(λ)=2.25∗109−1.5∗1015λ [Wm^-2m^-1] for 500nm<λ<1500nm

Where the wavelength λ is expressed in meters.

Calculate the short circuit current density Jsc (in mA/cm2) of a solar cell if the solar cell is measured under the solar simulator under STC.
EQE=0.8 for 300nm<λ<500nm

All, anything on this yet? please help!!! Thanks in advance again./Anon1...didn't know there was an Anon already

Someone please help me. I keep getting the same wrong answer (38.4). Please help ASAP. Thanks.

Correction: A is defined over range: 300nm to 700nm with EQE=0.8 for this range. Please help. I integrated over the range 300-500 & 500-700 using the two equations but not getting it.

Hello Ken, could you provide any insights? Thanks.

To calculate the short circuit current density (Jsc) of a solar cell under the solar simulator, we need to determine the total power incident on the solar cell. The equation for current density, J, is given by:

J = (Power incident on the solar cell) / (Area of the solar cell)

First, we need to calculate the power incident on the solar cell for each wavelength range.

1. For 300nm < λ < 500nm:
- The spectral power density equation is given as P(λ) = 7.5∗10^15λ^-2.25∗10^9 [Wm^(-2)m^(-1)].
- To calculate the power incident on the solar cell for this wavelength range, we need to integrate the spectral power density equation over the wavelength range.
- We integrate P(λ) with respect to λ, from 300nm to 500nm.
- The integral of P(λ) for this wavelength range gives us the power incident on the solar cell.

2. For 500nm < λ < 1500nm:
- The spectral power density equation is given as P(λ) = 2.25∗10^9−1.5∗10^15λ [Wm^(-2)m^(-1)].
- Similar to the previous step, we need to integrate P(λ) with respect to λ, from 500nm to 1500nm.
- The integral of P(λ) for this wavelength range gives us the power incident on the solar cell.

Once we have determined the power incident on the solar cell for both wavelength ranges, we can add them together to get the total power incident on the solar cell.

Finally, we divide the total power incident on the solar cell by the area of the solar cell to get the short circuit current density (Jsc).

Note: To convert Jsc to mA/cm^2, you will need to perform any necessary unit conversions.

I hope this explanation helps!