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July 29, 2014

July 29, 2014

Posted by **Ahlelie Reyes** on Thursday, November 28, 2013 at 3:28am.

Please show the complete solutions and answer. Thank you! :)

- Trigonometry -
**Steve**, Thursday, November 28, 2013 at 7:36amAt 5 pm, the ship is 30 miles south of its 3pm position. The distance from the lighthouse at 3pm is thus

d/30 = tan52°

so, d=38.4

Now, to get the distance at any other elapsed time of t hours,

d^2 = 38.4^2 + (15t)^2

Let 'er rip!

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