Posted by karthi on Wednesday, November 27, 2013 at 1:01pm.
Consider the function f(x)= 3
a) Determine any restrictions on x.
b) State the domain and range.
c) State equation(s) for the asymptote(s).
d) Determine any x- and y-intercepts.
e) Sketch a graph of the function.
f) Describe the behaviour of the function as x approaches -5 and 5.
someone please kindly do this for me please. i beg you, please do all these for me please....
- math - Steve, Wednesday, November 27, 2013 at 3:57pm
f(x) is not defined when the denominator is zero. So,
(a) x ≠ ±5
(b) domain is all reals except ±5
The denominator is minimum when x=0, so f(x) < -3/25 when -5<x<5
For |x| > 5 f(x) > 0, so the range is
(c) vertical: x=±5
(d) x: none
(e) see wolframalpha.com
(f) x -> +∞ for |x| > 5
x -> -∞ for |x| < 5
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