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March 6, 2015

March 6, 2015

Posted by **Nicole** on Tuesday, November 26, 2013 at 5:30pm.

In simpler terms it would look like this:

2x^4 X y^-4 X z^-3

-------------------

3x^2 X y^-3 X z^4

When I tried to solve this I got 6x^2 X y^-1 X 2^-7. Am I correct? If not could you please help me on how to solve it.

- Math #2 -
**Steve**, Tuesday, November 26, 2013 at 6:04pmNope. The coefficients just divide normally: 2/3

x^4/x^2 = x^2

y^-4/y^-3 = y^-1

z^-3/z^4 = z^-7

so, you wind up with

2/3 x^2 y^-1 z^-7, or

2x^2

--------

3yz^7

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