A stone propelled from a catapult with a speed of 50m/s attains a height of 100m.

calculate:
a.the time of flight
b.the angle of projection
c.the range attained:

velocity of stone=50m/s

height attained=100m
therefore,
time of flight=T=2Usin¤/g,
But time taken to get up to 100m=t1=Usin¤/g
..NOTE..
formula for time of flight=t1 was gotten from 2nd equation of motion which is equal to=S=UT+1/2AT SQUARED...
SUBSTITUTING THE GIVEN PARAMETERS,
S=100m
U=0
A=G=10ms
T=UNKNOWN=X
therefore,after working,
you will definetly get a value for t1 which would be approximately 4.something..in other to get total time of flight,T=2timest1...

coprehensively and secondly,
in other to get uhe angle of projection correctly,we apply the full formula total time of flight which has titan in it,after taking correct caculation,you will get the absolute angle of projection which is between 30 to 40,

lastly,you follow other protocols to get the range etc..for more answers to physics secondary questions,heres my number >08169373301

I. Don't understand this

Answer t0 this question

That's not correct

To calculate the time of flight, angle of projection, and range attained, we can use the equations of motion for projectile motion.

a. Time of Flight:
The time of flight refers to the total time it takes for the stone to reach its maximum height (apex) and return to the ground. In projectile motion, the time of flight can be calculated using the equation:

time of flight = (2 * vertical speed) / acceleration due to gravity

Since the stone is propelled vertically, the vertical speed is the vertical component of the initial velocity, given by:

vertical speed = initial velocity * sin(angle of projection)

The acceleration due to gravity can be approximated to 9.8 m/s².

Therefore, the time of flight is calculated as follows:

time of flight = (2 * (50 m/s * sin(angle of projection))) / 9.8 m/s²

b. Angle of Projection:
The angle of projection can be calculated using the equation:

angle of projection = arctan((vertical speed * time of flight) / (horizontal speed))

In this case, the horizontal speed remains constant throughout the motion and is given by the horizontal component of the initial velocity, which is:

horizontal speed = initial velocity * cos(angle of projection)

By substituting the values, we can rearrange the equation to solve for the angle of projection.

c. Range Attained:
The range refers to the horizontal distance covered by the stone. It can be calculated using the equation:

range = horizontal speed * time of flight

Substituting the values, we can calculate the range attained.

Please note that to calculate the angle of projection accurately, we need additional information, such as the horizontal distance covered by the stone. Without this information, we can approximate the angle using the maximum height attained and the known values of initial velocity and acceleration due to gravity.

v = 50 m/s

h = 100 m = x

x = 1/2 at^2

t = (square root) x/(1/2)

t = 4.51 s

Vi = 50 m/s so you have to find the final speed if you want to find the angle of projection, vi = 0 m/s i think cannot be zero

vf^2 = vi^2 + 2ad

I'm sorry you're going to have to look up this. Or maybe the other tutors here will help you. But I'm thinking you might have to include sin/speed to find the angle of projection

APPLY THE PARAMETERS,YOU HAVE T AS ZERO(0)

T=gt,t=50;>100=150

8.94s, 64.43, 2oom

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