How much do 8.36 × 1022 molecules of water
weigh?
Answer in units of grams
Please HELP this assignment is due literally in an hour and these are the last two questions i don't get. Anything helps.
mols = 8.36E22/6.02E23 = ?
Then mass = mols x molar mass = mols x 18 = ?
To find the weight of 8.36 × 10^22 molecules of water in grams, we need to know the molar mass of water (H2O).
1. Start by calculating the molar mass of water:
The molar mass of hydrogen (H) is approximately 1.008 grams/mol, and the molar mass of oxygen (O) is approximately 16.00 grams/mol. Since water (H2O) consists of two hydrogen atoms and one oxygen atom, we add the molar masses together:
Molar mass of water (H2O) = 2 * molar mass of hydrogen (H) + molar mass of oxygen (O)
= 2 * 1.008 grams/mol + 16.00 grams/mol
= 2.016 grams/mol + 16.00 grams/mol
= 18.016 grams/mol
2. Now that we know the molar mass of water, we can use it to convert the number of molecules to grams.
8.36 × 10^22 molecules (water) * (1 mol / 6.022 × 10^23 molecules (water)) * (18.016 grams / 1 mol)
= (8.36 × 10^22 molecules) * (18.016 grams / 6.022 × 10^23 molecules)
= (8.36 × 18.016) grams / 6.022
Evaluating the expression, the weight of 8.36 × 10^22 molecules of water is approximately 2.507 grams.