A school club consist of 30 male students and 13 female students. If 3 students are selected to represent the club in the student government, what is tge probability 2 will be male and 1 will be female?

please help me

prob

= C(30,2) x C(13,1)/C(43,3)
= 435(13)/12341
= .4582..

13/43 * 30/43* 30/43

Unless I am wrong. This may be more complicated than I think.

Why did the male student join the student government? Because he wanted to show off his excellent tie-lection skills! But fret not, I'm here to help with the probability question.

To calculate the probability of selecting 2 male students and 1 female student from the club, we need to consider the total number of possible combinations.

The total number of students in the club is 30 (male) + 13 (female) = 43.

First, let's calculate the probability of selecting a male:

Probability of selecting a male = Number of male students / Total number of students
= 30 / 43

Once we've selected one male student, we are left with 29 male students. So, let's calculate the probability of selecting a second male after the first male has been chosen:

Probability of selecting a second male = Number of remaining male students / Remaining total number of students
= 29 / 42

Now, let's calculate the probability of selecting a female student after the two males have already been chosen:

Probability of selecting a female = Number of female students / Remaining total number of students
= 13 / 41

Since we want to calculate the probability of selecting 2 males and 1 female, we multiply these probabilities:

Probability of selecting 2 males and 1 female = Probability of selecting a male * Probability of selecting a male * Probability of selecting a female

Thus,

Probability of selecting 2 males and 1 female = (30/43) * (29/42) * (13/41)

Now just do a bit of math to calculate the final answer and you're good to go!

To determine the probability of selecting 2 males and 1 female, we need to calculate the number of ways this can occur and divide it by the total number of possible outcomes.

Step 1: Calculate the number of ways to select 2 males from the 30 male students. This can be done using the combination formula, denoted as C(n, k), where n is the total number of items and k is the number of items to be chosen. In this case, we need to choose 2 males from the 30 available males. This can be calculated as:

C(30, 2) = 30! / (2!(30-2)!) = 435

Step 2: Calculate the number of ways to select 1 female from the 13 female students. This can be done using the combination formula as well. In this case, we need to choose 1 female from the 13 available females. This can be calculated as:

C(13, 1) = 13! / (1!(13-1)!) = 13

Step 3: Calculate the total number of possible outcomes by choosing 3 students from the total number of students (male + female). In this case, we need to choose 3 students from the total of 43 students (30 males + 13 females). This can be calculated as:

C(43, 3) = 43! / (3!(43-3)!) = 11,287

Step 4: Calculate the probability by dividing the number of favorable outcomes (2 males and 1 female) by the total number of possible outcomes:

Probability = (435 * 13) / 11,287 ≈ 0.498

Therefore, the probability that 2 students selected will be male and 1 student will be female is approximately 0.498 or 49.8%.

To find the probability of selecting 2 males and 1 female out of the total number of students, you need to use the concept of combinations.

First, you need to calculate the total number of ways to select 3 students out of the total of 43 students (30 males + 13 females). This can be calculated using the combination formula, given by:

nCr = n! / (r!(n - r)!)

Where n is the total number of items and r is the number of items to be selected.

In this case, n = 43 (total number of students) and r = 3 (students to be selected).

nCr = 43! / (3!(43 - 3)!)
= 43! / (3! * 40!)

Next, you need to calculate the number of ways to select 2 males out of the 30 males and 1 female out of the 13 females. You can use combinations again.

For males:
nCr = 30! / (2!(30 - 2)!)
= 30! / (2! * 28!)

For females:
nCr = 13! / (1!(13 - 1)!)
= 13! / (1! * 12!)

To find the total number of ways to select 2 males and 1 female, you need to multiply the combinations for males and females:

Total ways = (30! / (2! * 28!)) * (13! / (1! * 12!))

Finally, to find the probability, you divide the total ways by the total number of ways to select 3 students (which we found earlier):

Probability = (Total ways) / (Number of total ways to select 3 students)